Question

205.94\angle -90.32^\circ V, 205.94\angle +149.68^\circ V. Given the following balanced three-phase circuit 208\angle 0 3+j4 200\angle -20 Z_L 3+j4 a) Draw the per phase equivalent circuit. b) Calculate $I_a$. (ans: 13.35+j5 A) c) Find the impedance of the load $Z_L$ (ans: 10.66-j9.12$\Omega$) Given the following circuit 440\angle -240 440\angle 0 12+j12 12+j12 12+j12 440\angle -120 a) Draw the per phase equivalent circuit. b) Find the current $I_a$. (ans: $I_a = 3.87 - j4.46$ A) c) Find the source current $I_{in}$ (ans: $I_{in} = 6.11 - j6.11$ A)

          205.94\angle -90.32^\circ V,
205.94\angle +149.68^\circ V.
Given the following balanced three-phase circuit
208\angle 0
3+j4
200\angle -20
Z_L
3+j4
a) Draw the per phase equivalent circuit.
b) Calculate $I_a$. (ans: 13.35+j5 A)
c) Find the impedance of the load $Z_L$ (ans: 10.66-j9.12$\Omega$)
Given the following circuit
440\angle -240
440\angle 0
12+j12
12+j12
12+j12
440\angle -120
a) Draw the per phase equivalent circuit.
b) Find the current $I_a$. (ans: $I_a = 3.87 - j4.46$ A)
c) Find the source current $I_{in}$ (ans: $I_{in} = 6.11 - j6.11$ A)

205.94∠-90.32^∘V,
205.94∠+149.68^∘V.
Given the following balanced three-phase circuit
208∠0
3+j4
200∠-20
ZL
3+j4
a) Draw the per phase equivalent circuit.
b) Calculate Ia. (ans: 13.35+j5 A)
c) Find the impedance of the load ZL (ans: 10.66-j9.12Ω)
Given the following circuit
440∠-240
440∠0
12+j12
12+j12
12+j12
440∠-120
a) Draw the per phase equivalent circuit.
b) Find the current Ia. (ans: Ia = 3.87 - j4.46 A)
c) Find the source current Iin (ans: Iin = 6.11 - j6.11 A)

Added by Kathleen F.

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