20cm to the right of a +0.5x10^-6C charge is -2.1x10^-6C charge. Where, (relative to the +0.5x10^-6C charge) would a free electron be if the net electric force on the electron is 0?
Added by Kayley C.
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Given: Charge Q1 = +0.5x10^-6 C Distance from Q1 to point B = 20 cm = 0.2 m Electric field due to Q1 at point B: E1 = k * |Q1| / r^2 where k is the electrostatic constant (8.99x10^9 Nm^2/C^2) ** Show more…
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