20t college algebra home 54 ellipses jump to level 1 enter...

20T: College Algebra home > 5.4: Ellipses Jump to level 1 Enter the center for the given ellipse: ((x-4)^(2))/(36)+((y+4)^(2))/(9)=1 20T:College Algebra home>5.4:Ellipses EX-2,-2 36 Jump to level1 -=1 Enter the center for the given ellipse:

Transcript

00:01 Hello friends we have to find the center vertices and the focus and the centricity of the given ellipse the equation of ellipse is given 9x square plus 4 y square 9 x squared plus 4y square minus 54 x minus 54 x plus 40y plus 37 equals to 0 now we can write it like this 9 x square minus 6x plus 4 y square plus 10 y plus 37 equals to 0 and now we can write it x square minus 6x plus 9 minus 9 plus 4 y square plus 10 y plus 10 y plus 10 y plus 25 minus 20 plus 37 equals to 0 and further we can simplify it then it can be 9 x minus 3 whole square plus 4 y plus 5 whole square equals to 144 further we can write it live is x minus 3 whole square y 16 plus y plus 5 whole square y 36 equals to to 1 now we will compare it with the standard form of the ellipse that is x minus h whole square by b square plus y minus k whole square by a square equals to ver where h 6 b h 4 and the center of the ellipse will be center h comma k will be 3.

02:24 Minus 5 3 comma minus 5 okay now we will try to draw the ellipse ellipse will be like this okay this will be like this and the center of this will be 3 comma minus 5 the value of a is 6 that is a equals to 6 and this is b that is 4 suppose these are the focus and we know that this d1 plus d2 for this point d1 plus d2 equals to length of the major axis that is twice of a so we can write it is under root of that is focus if this for center to focus is distance c and this will be then d1 is and even in d2 equal to b squared plus c squared so it will be a then c will be a square minus b square square root of then c will be 36 minus 16 that is 20 c will be 2 root 5 c will be equal to 2 root 5 the vertices will be h comma k plus minus a that is h is 3 and kage minus 5 plus minus 6 so vertices will be 3.

04:50 Minus 11 and 3 .1 this will be your vertices and the focus h comma k plus minus c that is 3 comma k is minus 5 plus minus square root of 2 into square root of 5 so, this will be focus and the eccentricity will be e, that is c by a...

Question

20T: College Algebra home > 5.4: Ellipses Jump to level 1 Enter the center for the given ellipse: ((x-4)^(2))/(36)+((y+4)^(2))/(9)=1 20T:College Algebra home>5.4:Ellipses EX-2,-2 36 Jump to level1 -=1 Enter the center for the given ellipse:

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