21. How much energy is released in the formation of 612 g of...

21. How much energy is released in the formation of 612 g of PCl3 (137.32 g/mol), according to the balanced chemical equation? P4 (s) + 6 Cl2 (g) ? 4 PCl3 (g) ?H°rxn = -1207 kJ A. 5.38 × 10^3 kJ D. 1.85 × 10^3 kJ B. 4.76 × 10^3 kJ E. 1.34 × 10^3 kJ C. 3.46 × 10^3 kJ

The fat, $\mathrm{C}_{57} \mathrm{H}_{104} \mathrm{O}_{6}(\mathrm{~s})$, is metabolized via the following reaction. Given the enthalpies of formation, calculate the energy $(\mathrm{kJ})$ liberated when $1.0 \mathrm{~g}$ of this fat reacts. $$ \begin{gathered} \mathrm{C}_{57} \mathrm{H}_{104} \mathrm{O}_{6}(\mathrm{~s})+80 \mathrm{O}_{2}(g) \longrightarrow 57 \mathrm{CO}_{2}(g)+52 \mathrm{H}_{2} \mathrm{O}(l) \\ \Delta_{f} H^{\circ}\left(\mathrm{C}_{57} \mathrm{H}_{104} \mathrm{O}_{6}, s\right)=-70870 \mathrm{~kJ} / \mathrm{mol} ; \Delta_{f} H^{\circ}\left(\mathrm{H}_{2} \mathrm{O}, l\right)=-285.8 \mathrm{~kJ} / \mathrm{mol} ; \\ \triangle_{f} H^{\circ}\left(\mathrm{CO}_{2}, g\right)=-393.5 \mathrm{~kJ} / \mathrm{mol} \end{gathered} $$ (a) $-37.98$ (b) $-40.4$ (c) $-33.4$ (d) $-30.2$ be $-1$

Question

21. How much energy is released in the formation of 612 g of PCl3 (137.32 g/mol), according to the balanced chemical equation? P4 (s) + 6 Cl2 (g) ? 4 PCl3 (g) ?H°rxn = -1207 kJ A. 5.38 × 10^3 kJ D. 1.85 × 10^3 kJ B. 4.76 × 10^3 kJ E. 1.34 × 10^3 kJ C. 3.46 × 10^3 kJ

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