00:02
So if we're given two diffusions, d1 let's say is equal to 4 times 10 to the negative first meters per second.
00:11
Let's say d2 is equal to 8 times 10 to the negative 1 meters per second.
00:19
Well the diffusion in terms of a formula is going to be equal to the kinetic energy kbt, boltzmann's constant, times temperature divided by 6 pi eta times your radius.
00:35
In other words, eta is your viscosity and your viscosity is equal to some constant that's associated with the particle times e raised to the activation energy over rt.
00:57
Right, so this is, this is, let's see, this is sort of saying that the viscosity, at least the way we're going to use it, has no relationship with the radius or the diameter of the object that we're dealing with.
01:15
And let's say the object that we're dealing with is a spherically symmetric one, right, so we know about certain qualities of spheres.
01:25
Now we have the diffusion, the formula for the second one, both of them are the same, so it'll be kbt over 6 pi eta r.
01:38
Now we'll say this is radius 1 and this is radius 2, we can even say it's eta 1 and 2, but as we see eta is going to be, the, the, the viscosity is more to do with the energy, activation energy i would say for these particles than it would be for anything else, not necessarily the radius.
01:59
So let's look at the relationship between these two.
02:02
First of all, if b2 is larger that means r2 has to be smaller, so we know immediately that r2 is going to be less than r1 according to this, according to the formula that we have, but that should make sense...