Question

21. The formation of ethyl alcohol (C2H5OH, 46.07 g/mol) by the fermentation of glucose (C6H12O6, 180.16 g/mol) is represented by: C6H12O6 ? 2C2H5OH + 2CO2 If a particular glucose fermentation process is 87.0% efficient (i.e. the reaction has 87.0 % yield), how many grams of glucose would be required for the production of 51.0 g of ethyl alcohol? a. 68.3 g b. 75.1 g c. 115 g d. 229 g e. 99.7 g

          21. The formation of ethyl alcohol (C2H5OH, 46.07 g/mol) by the fermentation of glucose (C6H12O6, 180.16 g/mol) is represented by:
C6H12O6 ? 2C2H5OH + 2CO2
If a particular glucose fermentation process is 87.0% efficient (i.e. the reaction has 87.0 % yield), how many grams of glucose would be required for the production of 51.0 g of ethyl alcohol?
a. 68.3 g
b. 75.1 g
c. 115 g
d. 229 g
e. 99.7 g

Show more…

21. The formation of ethyl alcohol (C2H5OH, 46.07 g/mol) by the fermentation of glucose (C6H12O6, 180.16 g/mol) is represented by:
C6H12O6 ? 2C2H5OH + 2CO2
If a particular glucose fermentation process is 87.0% efficient (i.e. the reaction has 87.0 % yield), how many grams of glucose would be required for the production of 51.0 g of ethyl alcohol?
a. 68.3 g
b. 75.1 g
c. 115 g
d. 229 g
e. 99.7 g

Added by Vicente Z.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adi S

06/18/2024

Step 1

First, we need to find the moles of ethyl alcohol produced. We can do this by dividing the mass of ethyl alcohol by its molar mass: moles of ethyl alcohol = (51.0 g) / (46.07 g/mol) = 1.107 moles Show more…

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The formation of ethyl alcohol (C2H5OH, 46.07 g/mol) by the fermentation of glucose (C6H12O6, 180.16 g/mol) is represented by: C6H12O6 → 2C2H5OH + 2CO2. If a particular glucose fermentation process is 87.0% efficient (i.e. the reaction has 87.0% yield), how many grams of glucose would be required for the production of 51.0 g of ethyl alcohol? a. 68.3 g b. 75.1 g c. 115 g d. 229 g e. 99.7 g

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