Question

22. 3.7E The electric field in region \( B \) is: \( -\frac{\sigma}{\epsilon_{0}} \) \( -\frac{\sigma}{2 \epsilon_{o}} \) 0 \( +\frac{\sigma}{2 \epsilon_{o}} \) \( +\frac{\sigma}{\epsilon_{0}} \) 23. 3.7F The electric field in region \( C \) is: \( -\frac{\sigma}{\epsilon_{0}} \) \( -\frac{\sigma}{2 \epsilon_{o}} \) 0 \( +\frac{\sigma}{2 \epsilon_{o}} \) \( +\frac{\sigma}{\epsilon_{0}} \)

          22. 3.7E
The electric field in region \( B \) is:
\( -\frac{\sigma}{\epsilon_{0}} \)
\( -\frac{\sigma}{2 \epsilon_{o}} \)
0
\( +\frac{\sigma}{2 \epsilon_{o}} \)
\( +\frac{\sigma}{\epsilon_{0}} \)
23. 3.7F
The electric field in region \( C \) is:
\( -\frac{\sigma}{\epsilon_{0}} \)
\( -\frac{\sigma}{2 \epsilon_{o}} \)
0
\( +\frac{\sigma}{2 \epsilon_{o}} \)
\( +\frac{\sigma}{\epsilon_{0}} \)

22. 3.7E
The electric field in region B is:
-(σ)/(ϵ0)
-(σ)/(2 ϵo)
0
+(σ)/(2 ϵo)
+(σ)/(ϵ0)
23. 3.7F
The electric field in region C is:
-(σ)/(ϵ0)
-(σ)/(2 ϵo)
0
+(σ)/(2 ϵo)
+(σ)/(ϵ0)

Added by Deborah B.

Arihant AIEEE Physics

D.B. Singh 2006 Edition

Chapter 25

Instant Answer

Solved by Expert Prabhat Tyagi

Step 1

We are asked to find the electric field in regions B and C. The options given for the electric field values are in terms of \( \sigma \) (surface charge density) and \( \epsilon_0 \) (the permittivity of free space). This suggests we are dealing with a scenario Show more…

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22. 3.7E The electric field in region \( B \) is: \( -\frac{\sigma}{\epsilon_{0}} \) \( -\frac{\sigma}{2 \epsilon_{o}} \) 0 \( +\frac{\sigma}{2 \epsilon_{o}} \) \( +\frac{\sigma}{\epsilon_{0}} \) 23. 3.7F The electric field in region \( C \) is: \( -\frac{\sigma}{\epsilon_{0}} \) \( -\frac{\sigma}{2 \epsilon_{o}} \) 0 \( +\frac{\sigma}{2 \epsilon_{o}} \) \( +\frac{\sigma}{\epsilon_{0}} \)