0:00
Hi there.
00:01
So for this problem, we have the mariana trench that is located in the floor of the pacific ocean at a depth of about 11 ,000 meters below the surface of the water, and is shown in this figure.
00:16
The density of sea water has a value of 1 ,025 kilograms per meter cube, and and we need to determine first, for the first part of this problem, if an underwater vehicle were to explore such a death, what force would the water exert on a vehicle observation window? so we have a window, this in here, this window, and it has a radius of 0 .1 meters.
01:01
So for part a of this problem, we need to call q2.
01:04
The force exerted by the water in this window of radius 0 .1 meters.
01:16
Now, the magnitude of the force that will be inserted on the window is given by the following equation.
01:25
We know that the force relates with the pressure by the product between the pressure and the area of the application of the force.
01:33
And we can find the pressure by knowing that the pressure at a given depth is given by the atmospheric pressure plus the gauge pressure that is caused by the depth so that will be the density of the liquid in this case the density of sea water times the acceleration due to gravity and age which is the hate or the death in this case under the surface of the water.
02:09
Now, we can substitute this expression in the pressure that will experience the window at that death.
02:25
So we can substitute that, so we will find that the force is equal to the atmosphere pressure plus the gauge pressure times.
02:35
The area and the area of application is the area of the window.
02:41
So with that said, we can see that the area of that window is the area of a circle, which is pi times its radius square.
02:53
So for party of this problem, we just need to simply substitute all of the values that we know...