22.0 mL of 0.100 M NaOH is required to titrate 0.500 g of a mixture containing ascorbic acid. Calculate the % ascorbic acid in the mixture. (The molar mass of ascorbic acid is 176.13 g/mol)
Added by Ivan D.
Step 1
Given: Volume of NaOH = 22.0 mL = 0.0220 L Molarity of NaOH = 0.100 M Moles of NaOH = Molarity x Volume (in L) Moles of NaOH = 0.100 mol/L x 0.0220 L Moles of NaOH = 0.00220 moles Show more…
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