2. (20 pts) A block of mass m = 5.00kg is sitting on an inclined frictionless surface with $\theta$ = 30° to the horizontal direction. The block slides a distance d = 5.00m down the inclined surface and contacts an unstressed spring. The block slides an additional distance x as the spring is compressed the most (this is also when the block's speed is 0 m/s). Spring constant k = 2.00 N/m. Find the distance x.
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First, let's determine the initial velocity of the block. We can use the equation for the final velocity of an object sliding down an inclined plane without friction: v = sqrt(2gh) where v is the final velocity, g is the acceleration due to gravity (9.8 m/s^2), Show more…
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