00:01
Hello students, according to this question we are going to find out the output voltage.
00:05
To solve this question we are going to use kcl, kirchhoff's current law at node 1.
00:15
First we are going to see node 1.
00:18
From this i am going to take 2 milliampere is equal to, that means current, is equal to v1 divided by 5 kilo ohms.
00:29
Instead of resistance i am just writing it as 5 kilo ohms plus v1 minus vn divided by 20 kilo ohms plus v1 minus v0 divided by 10 kilo ohms.
00:50
Now while taking the lcm we will get the value as equation as 40 is equal to 4v1 plus v1 minus vn plus 2vn minus 2v0.
01:11
Resolving this we will get the equation as 7v1 minus 2v0 is equal to 40.
01:33
This is the first equation.
01:34
Next we are going to use the kcl at node 2.
01:44
Now vn minus v1 divided by 20 kilo ohms plus vn minus v0 divided by 10 kilo ohms plus vn is equal to 0.
02:13
While doubling the values we will get 0 minus v1 divided by 20 kilo ohms plus 0 minus v0 divided by 10k plus 0.
02:30
This value is 0...