23. How many grams of water is produced when 35.0 grams of methane, CH4, reacts with oxygen, O2, in the following balanced equation CH4 + 2 O2 → CO2 + 2 H2O Group of answer choices 4.38 g 78.8 g 126 g 39.4 g
Added by Alejandro M.
Step 1
Molar mass of CH4 = 12.01 g/mol (C) + 4 * 1.01 g/mol (H) = 16.05 g/mol Molar mass of H2O = 2 * 1.01 g/mol (H) + 16.00 g/mol (O) = 18.02 g/mol Now, we can find the moles of methane (CH4) in 35.0 grams: moles of CH4 = (35.0 g) / (16.05 g/mol) = 2.18 mol From Show more…
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