Question

23. Let X be normally distributed with mean ? = 2,500 and standard deviation ? = 800. a. Find x such that P(X ? x) = 0.9382. b. Find x such that P(X > x) = 0.025. c. Find x such that P(2500 ? X ? x) = 0.1217. d. Find x such that P(X ? x) = 0.4840.

          23. Let X be normally distributed with mean ? = 2,500 and standard deviation ? = 800.
a. Find x such that P(X ? x) = 0.9382.
b. Find x such that P(X > x) = 0.025.
c. Find x such that P(2500 ? X ? x) = 0.1217.
d. Find x such that P(X ? x) = 0.4840.

23. Let X be normally distributed with mean ? = 2,500 and standard deviation ? = 800.
a. Find x such that P(X ? x) = 0.9382.
b. Find x such that P(X > x) = 0.025.
c. Find x such that P(2500 ? X ? x) = 0.1217.
d. Find x such that P(X ? x) = 0.4840.

Added by Paula W.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Adi S

05/06/2024

Step 1

To find the value of x such that P(X < x) = 0.9382, we need to find the z-score corresponding to this probability. Using a standard normal table or calculator, we find that the z-score is approximately 1.55. Now, we can use the formula: x = μ + z * σ x = 2500 + Show more…

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23. Let X be normally distributed with mean μ = 2,500 and standard deviation σ = 800. a. Find x such that P(X ≤ x) = 0.9382. b. Find x such that P(X > x) = 0.025. c. Find x such that P(2500 ≤ X ≤ x) = 0.1217. d. Find x such that P(X ≤ x) = 0.4840.