00:01
Absorbed on charcoal to the extent that 0 .92, i'm going to put this on the next line, 0 .921, 0 .921 centimeters cubed, gram to the minus 1, at 490 kilopascals and 190 kelvin, but at 250 kelvin, the same amount, of adsorption was achieved when pressure was increased to 3 .2 megapascals.
01:42
Let me see if i got the everything right.
01:44
I want to make sure i got everything right.
01:48
190, 250.
01:54
Okay, and we are asked, what is the enthalpy of adsorption of nitrogen on charcoal? okay, let's see if i can figure this one out.
02:46
First, find the value of enthalpy of absorption.
03:07
And our equation equations are now for constant, excuse me, excuse me, excuse me.
04:25
I'm almost done with this part, and then i'm going to get my actual equation down here.
04:54
Wow.
05:00
This is the equation where you're going to use.
05:01
And we know r will be 8 .3145 j over kmo.
05:20
We know that p1 is 490 kilopascals and p2 is 3 .2 megapascals which equals 3 .2 times 10 to the third kilopascals...