00:01
Hi, so hearing this question we have given, the web function psi of x is 2 divided by root a, sine 5 pi x divided by a, cost 3 pi x divided by a.
00:13
Now, using the formula, sine a plus sine b, we will get, this web function will be 2 by root a, sine 8 pi x divided by a plus sine 2 pi x divided by a.
00:27
Now we will check normalization condition.
00:32
Therefore 4 divided by a integration from 0 to a, psi square that is sine 8 pi x divided by a plus sine 2 pi x divided by a d x will be equal to 4 divided by a squared by a, integration from 0 to a, sine square 8 pi x divided by a plus sine square 2 pi x divided by a, plus 2x divided by a, sign 2 pi x divided by a, sine 2 pi x divided by a, sine 2 pi x divided by x multiplied by d x now sign integration of since integration 0 to a sign n pi x divided by a d x is equal to a divided by 2 therefore we will get this will be equal to 4 divided by 2 therefore we will get this will be equal to 4 divided by by a multiplied by a divided by 2 plus a divided by 2.
02:18
Then this will be equal to 4.
02:28
Then the normalized wave function will be equal to si of x 2 upon 2 root a, sine 5 pi x divided by a, cost 3 pi x divided by a.
02:52
Call this as equation number 1.
02:55
To prove the boundary conditions, we will consider si of 0 will be equal to si of a equals to 0.
03:09
As si of 0 is equal to 0, then si of a equals to 1 upon root a, sine 5 pi cost 3 pi which will be equal to 0 as sine 5 pi will be equal to 0.
03:36
Therefore we can say that boundary conditions are satisfied.
03:56
Now in part b or second part we have from equation 1, x x is equal to 1 upon root a, sine 5 pi x divided by a, cos 3 pi x divided by a, which can be written as 1 divided by root a, sign 8 pi x divided by a plus cos 3 pi x divided by a let me sign 2 pi x divided by a that is 1 divided by root a sign 8 pi x divided by a plus 1 divided by root a sine 2 pi x divided by a, which can be written as a, phi, psi of p of x plus b, si, q of x, where si p of x will be equal to sine 8 pi x divided by a and si q of x will be equal to sine 2 pi x divided by a and also a equals to b will be equal to 1 divided by root a which implies p will be equal to 8 and q will be equal to 2...