5. A 9.883 mL sample of 1.8285 M HCl (molar mass = 36.46 g/mol) solution requires 37.82 mL of NaOH (molar mass = 40.00 g/mol) solution for complete neutralization: (10) a) Calculate the volume of NaOH in Litres required for the titration? b) Calculate the volume of HCl in Litres required for titration c) Calculate the molarity of NaOH solution
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We can do this using the given volume and molarity of the HCl solution. Moles of HCl = Molarity × Volume Moles of HCl = 0.8285 M × 0.02353 L = 0.01948 moles Now, we know that the neutralization reaction between HCl and NaOH is a 1:1 reaction, so the moles of Show more…
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