Question

4. 2x\textsuperscript{2}+7x-15=0 If r and s are two solutions of the equation above and r > s, which of the following is the value of r - s? A) \frac{15}{2} B) \frac{13}{2} C) \frac{11}{2} D) \frac{3}{2}

          4.
2x\textsuperscript{2}+7x-15=0
If r and s are two solutions of the equation above
and r > s, which of the following is the
value of r - s?
A) \frac{15}{2}
B) \frac{13}{2}
C) \frac{11}{2}
D) \frac{3}{2}

4.
2x2+7x-15=0
If r and s are two solutions of the equation above
and r > s, which of the following is the
value of r - s?
A) (15)/(2)
B) (13)/(2)
C) (11)/(2)
D) (3)/(2)

Added by Ricardo H.

Geometry A Common Core Curriculum

Ron Larson, Laurie Boswell 1st Edition

Instant Answer

Solved by Expert Julie Silva

Step 1

Plugging these values into the formula, we get: $$x = \frac{-7 \pm \sqrt{7^2 - 4(2)(-15)}}{2(2)}$$ Simplify the expression inside the square root: $$x = \frac{-7 \pm \sqrt{49 + 120}}{4}$$ $$x = \frac{-7 \pm \sqrt{169}}{4}$$ Now, we can take the square root of Show more…

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