00:01
Here we'll be performing chi -square goodness of it.
00:05
H naught is the use of dental services between children living in boston is equal to the national data.
00:37
Alternate hypothesis will be the use of dental services between children living in boston is different from national data.
00:55
Let alpha that is level of significance be 0 .05.
01:00
Degrees of freedom is calculated as number of categories minus 1.
01:07
Here number of categories is 2 minus 1 is 1 as the degrees of freedom.
01:13
The observed frequency is denoted as o.
01:18
It is 65.
01:21
Total observation is 125.
01:26
So here it will be 60.
01:29
The proportion values are 0 .75.
01:33
1 minus 0 .75 is 2 .5.
01:38
The expected frequency is calculated as p into n...