240 MT #3 FIND-FIX-SOLVE FBD P W 18" 10" G Wsin60 Wcos60 Equilibrium Equation. $\sum M_B = 0$ $Wsin60(22) - Wcos60(10) - 18P = 0$ $P = \frac{210(22sin60 - 10cos60)}{18}$ $P = 163.9 lb$
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The equilibrium equation is given as: $\sum M_B = 0$ $Wsin60(22) - Wcos60(10) - 18P = 0$ $P = \frac{W(22sin60 - 10cos60)}{18}$ Show more…
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