Question

25. Using the diagram below and the given data , calculate ?H1; ?H2 and ?H4. H2(g at 100°C) + ½ O2(g at 100°C) --?Hrxn.--> H2O(liquid at 100°C) 1 | ?H1 4 | ?H4 ? ? H2(g at 25°C) + ½ O2(g at 100°C) 2 | ?H2 ? H2(g at 25°C) + ½ O2(g at 25°C) --?H3 = -285.839 kJ/mol--> H2O(liquid at 25°C) Cp(H2) 25°C to 100°C = 28.9 J deg-1mol-1 Cp(O2) 25°C to 100°C = 29.4 J deg-1mol-1 Cp(H2O) 25°C to 100°C = 75.5 J deg-1mol-1 A. ?H1 = -2.168 kJ/mol ?H2 = -1.103 kJ/mol ?H4 = +5.662 kJ/mol B. ?H1 = -2.168 kJ/mol ?H2 = -1.103 kJ/mol ?H4 = -5.662 kJ/mol C. ?H1 = -2.168 kJ/mol ?H2 = -2.206 kJ/mol ?H4 = -5.662 kJ/mol D. ?H1 = +2.168 kJ/mol ?H2 = +1.103 kJ/mol ?H4 = -5.662 kJ/mol

          25. Using the diagram below and the given data , calculate ?H1; ?H2 and ?H4.

H2(g at 100°C) + ½ O2(g at 100°C) --?Hrxn.--> H2O(liquid at 100°C)
1 | ?H1                                     4 | ?H4
?                                         ?
H2(g at 25°C) + ½ O2(g at 100°C)
2 | ?H2
?
H2(g at 25°C) + ½ O2(g at 25°C) --?H3 = -285.839 kJ/mol--> H2O(liquid at 25°C)

Cp(H2) 25°C to 100°C = 28.9 J deg-1mol-1
Cp(O2) 25°C to 100°C = 29.4 J deg-1mol-1
Cp(H2O) 25°C to 100°C = 75.5 J deg-1mol-1

A. ?H1 = -2.168 kJ/mol ?H2 = -1.103 kJ/mol ?H4 = +5.662 kJ/mol
B. ?H1 = -2.168 kJ/mol ?H2 = -1.103 kJ/mol ?H4 = -5.662 kJ/mol
C. ?H1 = -2.168 kJ/mol ?H2 = -2.206 kJ/mol ?H4 = -5.662 kJ/mol
D. ?H1 = +2.168 kJ/mol ?H2 = +1.103 kJ/mol ?H4 = -5.662 kJ/mol

25. Using the diagram below and the given data , calculate ?H1; ?H2 and ?H4.

H2(g at 100°C) + ½ O2(g at 100°C) –?Hrxn.–> H2O(liquid at 100°C)
1 | ?H1 4 | ?H4
? ?
H2(g at 25°C) + ½ O2(g at 100°C)
2 | ?H2
?
H2(g at 25°C) + ½ O2(g at 25°C) –?H3 = -285.839 kJ/mol–> H2O(liquid at 25°C)

Cp(H2) 25°C to 100°C = 28.9 J deg-1mol-1
Cp(O2) 25°C to 100°C = 29.4 J deg-1mol-1
Cp(H2O) 25°C to 100°C = 75.5 J deg-1mol-1

A. ?H1 = -2.168 kJ/mol ?H2 = -1.103 kJ/mol ?H4 = +5.662 kJ/mol
B. ?H1 = -2.168 kJ/mol ?H2 = -1.103 kJ/mol ?H4 = -5.662 kJ/mol
C. ?H1 = -2.168 kJ/mol ?H2 = -2.206 kJ/mol ?H4 = -5.662 kJ/mol
D. ?H1 = +2.168 kJ/mol ?H2 = +1.103 kJ/mol ?H4 = -5.662 kJ/mol

Added by Rach G.

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