2500 kJ of work is done by a 1250kg car as it goes on a 1.50km drive. If the drive is 1.50km long, what is the equivalent force, and change in energy that the car achieves?
Added by Brayden L.
Step 1
Given that the work done by the car is 2500 kJ, we can convert this to joules by multiplying by 1000 (1 kJ = 1000 J). 2500 kJ * 1000 = 2,500,000 J Show more…
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