00:01
Hi, a parallel plate capacitor is having an area which is 25 cm square that is equal to 25 into 10 power minus 4 meter square.
00:11
Now, a dielectric mediums of three different types are introduced between the parallel plate capacitors.
00:19
We have to find the capacitance in each case and also we have to tell for maximum capacitance we have to use which dialectic medium.
00:29
When a dialectic medium is introduced between the plates, the capacitance c -dash is equal to k into c -0, where c -not is equal to epsilon -not a by d.
00:41
So therefore c -d -d -c -d -d -k into epsilon -0 -a by d.
00:46
So here the dialectic mediums of different thickness are introduced.
00:53
So in the first case, paraffin is introduced which is having of d, the thickness as 1 -m.
01:02
Which is 1 into 10 power minus 3 meter.
01:06
So therefore the capacitance will be epsilon not a by d which is equal to 8 .85 into 10 power minus 12 into 25 into 10 power minus 4 divided by d is 1 into 10 power minus 3.
01:22
On solving we get 221 .25 into 10 power minus 13 parrot...