00:01
Hi, in this question, the free charge density in a copper wire is given as 8 .5 in 10 to over 28 electrons per cubic meter.
00:09
That is n is equal to 8 .5 into the power 28 electrons per cubic meter.
00:15
The electric field is given as 0 .06 newton per cool.
00:21
That is e is equal to 0 .06 neuter per kool.
00:24
The temperature in the wire is given as 20 degrees celsius.
00:29
The separation distance is given as d is equal to 20 cm, that is 0 .2 meters.
00:35
We need to determine the drift velocity of the electrons and the potential difference between the two points in the wire.
00:45
First of all, let us determine the drift velocity of the electrons which is given by vd is equal to e divided by r ru qn.
01:04
Where this e is the electric field, row is the resistivity of the copper wire and the resistivity of the copper wire is being taken as 1 .68 in the 10 borg, 0 .6 .8 o meter and the q is the amount of charge, n is the free charge density.
01:25
Now let us plug the given values and determine the drift speed of the electrons...