Question

26. A syringe contains 50.0 mL of a gas at a pressure of 101 kPa. The end is sealed and the plunger is pushed to compress the gas to a volume of 12.5 mL. What is the new pressure, assuming constant temperature? 27. Carbon dioxide produced by yeast in bread dough causes the dough to rise, even before it is baked (Figure 11). During baking, the carbon dioxide gas expands. Predict the final volume of 0.10 L of carbon dioxide in bread dough that is heated from 25°C to 190°C at a constant pressure. 28. A storage tank is designed to hold a fixed volume of butane gas at 150 kPa and 35°C. To prevent dangerous pressure buildup, the tank has a relief valve that opens at 250 kPa. At what (Celsius) temperature does the valve open? 29. A balloon has a volume of 5.00 L at 20°C and 100 kPa. What is its volume at 35°C and 90 kPa? 30. A cylinder of helium gas has a volume of 1.0 L. The gas in the cylinder exerts a pressure of 800 kPa at 30°C. What volume would this gas occupy at SATP? 31. For any of the calculations in the previous questions, does the result depend on the identity of the gas? Explain briefly.

          26. A syringe contains 50.0 mL of a gas at a pressure of 101 kPa. The end is sealed and the plunger is pushed to compress the gas to a volume of 12.5 mL. What is the new pressure, assuming constant temperature?
27. Carbon dioxide produced by yeast in bread dough causes the dough to rise, even before it is baked (Figure 11). During baking, the carbon dioxide gas expands. Predict the final volume of 0.10 L of carbon dioxide in bread dough that is heated from 25°C to 190°C at a constant pressure.
28. A storage tank is designed to hold a fixed volume of butane gas at 150 kPa and 35°C. To prevent dangerous pressure buildup, the tank has a relief valve that opens at 250 kPa. At what (Celsius) temperature does the valve open?
29. A balloon has a volume of 5.00 L at 20°C and 100 kPa. What is its volume at 35°C and 90 kPa?
30. A cylinder of helium gas has a volume of 1.0 L. The gas in the cylinder exerts a pressure of 800 kPa at 30°C. What volume would this gas occupy at SATP?
31. For any of the calculations in the previous questions, does the result depend on the identity of the gas? Explain briefly.

Show more…

26. A syringe contains 50.0 mL of a gas at a pressure of 101 kPa. The end is sealed and the plunger is pushed to compress the gas to a volume of 12.5 mL. What is the new pressure, assuming constant temperature?
27. Carbon dioxide produced by yeast in bread dough causes the dough to rise, even before it is baked (Figure 11). During baking, the carbon dioxide gas expands. Predict the final volume of 0.10 L of carbon dioxide in bread dough that is heated from 25°C to 190°C at a constant pressure.
28. A storage tank is designed to hold a fixed volume of butane gas at 150 kPa and 35°C. To prevent dangerous pressure buildup, the tank has a relief valve that opens at 250 kPa. At what (Celsius) temperature does the valve open?
29. A balloon has a volume of 5.00 L at 20°C and 100 kPa. What is its volume at 35°C and 90 kPa?
30. A cylinder of helium gas has a volume of 1.0 L. The gas in the cylinder exerts a pressure of 800 kPa at 30°C. What volume would this gas occupy at SATP?
31. For any of the calculations in the previous questions, does the result depend on the identity of the gas? Explain briefly.

Added by Patricia B.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sri K

05/29/2022

Step 1

0 mL) and pressure (P1 = 101 kPa), and the final volume (V2 = 12.5 mL) is compressed. According to Boyle's Law, P1V1 = P2V2. We can rearrange this equation to solve for P2: \[ P2 = \frac{P1 \times V1}{V2} \] Show more…

Show all steps

lock

Thanks for your feedback!

26. A syringe contains 50.0 mL of a gas at a pressure of 101 kPa. The end is sealed and the plunger is pushed to compress the gas to a volume of 12.5 mL. What is the new pressure, assuming constant temperature? 27. Carbon dioxide produced by yeast in bread dough causes the dough to rise, even before it is baked (Figure 11). During baking, the carbon dioxide gas expands. Predict the final volume of 0.10 L of carbon dioxide in bread dough that is heated from 25°C to 190°C at a constant pressure. 28. A storage tank is designed to hold a fixed volume of butane gas at 150 kPa and 35°C. To prevent dangerous pressure buildup, the tank has a relief valve that opens at 250 kPa. At what (Celsius) temperature does the valve open? 29. A balloon has a volume of 5.00 L at 20°C and 100 kPa. What is its volume at 35°C and 90 kPa? 30. A cylinder of helium gas has a volume of 1.0 L. The gas in the cylinder exerts a pressure of 800 kPa at 30°C. What volume would this gas occupy at SATP? 31. For any of the calculations in the previous questions, does the result depend on the identity of the gas? Explain briefly.

Play audio

Feedback

Powered by NumerAI

Sri K and 81 other subject Chemistry 101 educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Recommended Videos

Recommended Textbooks

Transcript

00:01 Hello, here we are given a set of six questions, but all of them are related to the ideal gas equation and the different ideal gas laws.

00:13 So let's start with question number 26, which uses the boils law.

00:20 So the boils law states that p1 v1 is equal to p2 v2 at constant temperature.

00:27 So the data given to us is that p1 is 101 kilopascals multiplied by v1.

00:35 V1 is 50 .0 ml that is equal to p2 is what we need to figure out and v2 is 12 .5.

00:45 So when we rearrange the terms, we get that p2 is equal to 101 kilo -pascals multiplied by 50 .0 0 .0 divided by 12 .5 emil.

00:58 So when we do this, we obtain 404 kilopascals.

01:03 This is the answer.

01:05 Let's move on to question 27, which uses the formula v1 by t1 is equal to v2 by t2.

01:14 So now we are given that v1 is 0 .10 liter divided by, we are given 25 degrees celsius, but you have to remember that we have to convert it into kelvin.

01:26 So 25 degrees celsius plus 273, we get 298 kelvin.

01:33 So divided by 298.

01:36 This is equal to v2 is what we are required to find divided by 190 degrees celsius plus 273 that is 4 63 kelvin upon the rearrangement and computation we obtain v2 is equal to 0 .155 liters this is the answer to the second question now question number 27 now let's move on to question number 28 where we are supposed to use a formula p1 by t1 is equal to p2 by t2 we are given p1 is equal to 150 kilo pascal divided by t1 which is 35 degrees celsius plus 273 we obtain 308 kelvin this is equal to we're given p2 as well which is 250 kilodd divided by t2 so upon cross multiplication we get t2 is equal to 513 .3 kelvin but here we're asked to find the answer in degrees celsius.

02:43 So we subtract 273 and we obtain the answer to 40 degrees celsius.

02:49 Here we're rounding 5 .3 .3.

02:51 So this is the final answer.

02:55 Now let's move on to question number 29...

Ace is your personal tutor. It breaks down any question with clear steps so you can learn.

Start Using Ace

Continue solving this problem

Create a free account to:

View full step-by-step solution
Ask follow-up questions with Ace AI
Save progress and study later