00:01
To calculate the final temperature, we'll use the heat equation, q, is equal to the specific heat of the water, multiplied by the mass of the water, multiplied by the change in temperature, which is the final temperature minus the initial temperature.
00:16
So if we add 980 kilojoules of energy, because the specific heat of water is in units of joules per gram degree celsius, we need to convert this.
00:31
To joules, one kilogram, sorry, kilojoule is 1 ,000 joules.
00:39
We'll set that equal to s, 4 .184, joules per gram degree celsius, multiplied by the mass of water, it's 6 .2 liters, and at a density of 1 gram per mill liter, that's 6 ,200 milliliters or 6 ,200 grams...