Question

26) The enthalpy of combustion of propane, C3H8, is -2202 kJ/mol. What amount of heat is liberated when a sufficient amount of propane is combusted to form 1.25 kg of carbon dioxide? a. 20.8 MJ b. 6.95 MJ c. 38.2 MJ d. 17.2 MJ e. 918 MJ 27) A 100.0 gram sample of pure copper at 89.3 oC is placed in a 100.0 gram sample of water at 25.1 oC. Assuming that the only heat flow is between the copper and the water, what is the temperature of the water after the copper and the water come to thermal equilibrium? (Note: the specific heat of copper is 0.385 J/goC.) a. 30.5 oC b. 18.6 oC c. 36.7 oC d. 15.5 oC e. 34.6 oC

          26) The enthalpy of combustion of propane, C3H8, is -2202 kJ/mol. What amount of heat is liberated when a sufficient amount of propane is combusted to form 1.25 kg of carbon dioxide?
a. 20.8 MJ
b. 6.95 MJ
c. 38.2 MJ
d. 17.2 MJ
e. 918 MJ 

27) A 100.0 gram sample of pure copper at 89.3 oC is placed in a 100.0 gram sample of water at 25.1 oC. Assuming that the only heat flow is between the copper and the water, what is the temperature of the water after the copper and the water come to thermal equilibrium? (Note: the specific heat of copper is 0.385 J/goC.)
a. 30.5 oC
b. 18.6 oC
c. 36.7 oC
d. 15.5 oC
e. 34.6 oC

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Added by Jessica J.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

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Solved by Expert Susan Hallstrom

05/03/2023

Step 1

25 kg of carbon dioxide. 1.25 kg of CO2 = 1250 g of CO2 Molar mass of CO2 = 44.01 g/mol Moles of CO2 = 1250 g / 44.01 g/mol = 28.4 mol Show more…

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26) The enthalpy of combustion of propane, C3H8, is -2202 kJ/mol. What amount of heat is liberated when a sufficient amount of propane is combusted to form 1.25 kg of carbon dioxide? a. 20.8 MJ b. 6.95 MJ c. 38.2 MJ d. 17.2 MJ e. 918 MJ 27) A 100.0 gram sample of pure copper at 89.3 oC is placed in a 100.0 gram sample of water at 25.1 oC. Assuming that the only heat flow is between the copper and the water, what is the temperature of the water after the copper and the water come to thermal equilibrium? (Note: the specific heat of copper is 0.385 J/goC.) a. 30.5 oC b. 18.6 oC c. 36.7 oC d. 15.5 oC e. 34.6 oC

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Transcript

00:01 We'll be considering the combustion of propane.

00:05 Let me jot that equation down quickly.

00:24 Let's see what they used here.

00:25 G.

00:28 Okay and we're told that we have 1 .00 grams of propane reacts exactly with oxygen.

00:38 Let's figure out how many moles that is.

00:49 I'm going to go check my molar mass out.

00:52 I was just going to write 44 but it might be a little more than that.

01:01 Propane is 44 .097.

01:04 So i'll go 44 .10.

01:14 1 divided by 44 .1 is 0 .0226757.

01:23 I'll round later.

01:29 Next we are told also the heat released is transferred to a calorimeter and the calorimeter contains 250 grams of water.

01:47 My change of temperature we are given that its temperature is going to rise to 62 degrees c from 20 degrees c.

02:00 That'll give us 48 .2 degrees c.

02:05 We're told that our specific heat of water that we're to use is 4 .18 j over g degrees c and the amount of heat.

02:17 Find the heat per 1 gram of c3h8 and my heat of reaction in units of kilojoules per mole.

02:40 Okay so our q will be equal to mc delta t.

02:50 That'll be 250 grams times 4 .18 joules per gram degrees c times 48 .2 degrees c.

03:07 I'm calculating and this will be equal to 50 ,369 joules and that's per gram.

03:27 So my joules per gram is equal to 50...

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