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26. The population of a bacteria colony is modelled by the function p(t) = 200 + 20t - t^2, where t is time, in hours, t >= 0, and p is the number of bacteria, in thousands. a) Determine the growth rate of the bacteria population at each of the following times. i) 3 h ii) 8 h iii) 13 h iv) 18 h b) What are the implications of the growth rates in part a)? c) Determine the equation of the tangent to p(t) at the point corresponding to t = 8. d) When does the bacteria population stop growing? What is the population at this time? e) Graph the growth function and its derivative. Describe how each graph reflects the rate of change of the bacteria population. f) Determine the time interval over which the bacteria population i) increases ii) decreases

          26. The population of a bacteria colony is modelled by the function p(t) = 200 + 20t - t^2, where t is time, in hours, t >= 0, and p is the number of bacteria, in thousands.
a) Determine the growth rate of the bacteria population at each of the following times.
i) 3 h ii) 8 h iii) 13 h iv) 18 h
b) What are the implications of the growth rates in part a)?
c) Determine the equation of the tangent to p(t) at the point corresponding to t = 8.
d) When does the bacteria population stop growing? What is the population at this time?
e) Graph the growth function and its derivative. Describe how each graph reflects the rate of change of the bacteria population.
f) Determine the time interval over which the bacteria population
i) increases ii) decreases
        
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26. The population of a bacteria colony is modelled by the function p(t) = 200 + 20t - t^2, where t is time, in hours, t >= 0, and p is the number of bacteria, in thousands.
a) Determine the growth rate of the bacteria population at each of the following times.
i) 3 h ii) 8 h iii) 13 h iv) 18 h
b) What are the implications of the growth rates in part a)?
c) Determine the equation of the tangent to p(t) at the point corresponding to t = 8.
d) When does the bacteria population stop growing? What is the population at this time?
e) Graph the growth function and its derivative. Describe how each graph reflects the rate of change of the bacteria population.
f) Determine the time interval over which the bacteria population
i) increases ii) decreases

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Elementary and Intermediate Algebra
Elementary and Intermediate Algebra
Alan S. Tussy, R. David Gustafson 5th Edition
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The population of a bacteria colony is modeled by the function p(t) = 200 + 20t - t^2, where t is time in hours (t >= 0), and p is the number of bacteria in thousands. a) Determine the growth rate of the bacteria population at each of the following times: i) 3 h ii) 8 h iii) 13 h iv) 18 h b) What are the implications of the growth rates in part a)? c) Determine the equation of the tangent to p(t) at the point corresponding to t = 8. d) When does the bacteria population stop growing? What is the population at this time? e) Graph the growth function and its derivative. Describe how each graph reflects the rate of change of the bacteria population. Determine the time interval over which the bacteria population: i) increases ii) decreases
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Transcript

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00:01 Hi, today we are solving the question in which population in terms of t is given as 200 plus 20t minus t square.
00:13 So if we take first we can see that from here time is given as 3 hours.
00:25 So if we put time as 3 hours so p at 3 will be given as 200 plus 20 into 3 minus 3 whole square.
00:38 So we get it equals to 251.
00:42 So population at 3 hours is 251.
00:48 Similarly, taking the next one so given as in a part this is second sub part so here time is given as 8 hours.
01:01 So if we take p as 8 similarly 200 plus 20 into 8 minus 8 whole square.
01:10 So we get it equals to 196.
01:13 Now similarly taking the third one time is given as 13 hours.
01:20 So we get it as similarly p13 will be equal to 291 and last we are given that time is equals to 18 hours.
01:32 So p18 will be equal to 236.
01:37 So from here therefore we get the required population p3 as 251, p8 as 196, p13 as 291, p18 as 236.
01:58 Now secondly we are taking in the interval from 8 to 13 moves it reaches the maximum and the decrease begins.
02:37 Now similarly taking the next one so here if we take the derivative of the given population so p dash t will be equal to 20 minus 2t...
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