2.67 ?? P2.67? ?? ???? ????? ???? ??? ??? 150 kg??, ???? ??? 1000 kN/m??, ????? 600 kg/s??. ????? ??? 3000 rev/min? ?????? 374 N?? ????. (a) ??? ?? ??? ??? ??? ????. (b) ????? ?? ??? 1%? ? ? e ?? ????.
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The given information includes various numbers and symbols such as 2.67, P, 2.67150 kg, 1000 kN/m, 600 kg/s, 3000 rev/min, 374 N, ab, 1%, e, A, 014-73, 014H-73, x(t), m, mo, and P2.67. Show more…
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relate force + motion => 2nd Law ΣFy2 = m2ay0 T - m2g = 0 T = (5.0kg)(9.8m/s²) T = 49N fr <= μsN want equal for "breaking point" fr is up because acting against gravity ΣFx1 = m1ax0 T + μsN - m1g sin 35° = 0 49N + 0.25 (m1 g cos 35) - m1 g sin 35° = 0 m1 (9.8 m/s²) [sin 35° - 0.25 cos 35°] = 49N m1 = 49N / (3.6m/s²) = 14 kg m1 g sin 35° T μsN m1 g cos 35° ΣFy1 = m1ay0 N - m1 g cos 35 = 0 N = m1 g cos 35 4.64
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