00:01
Here we have a chemical reaction of 2 moles h2 with 2 moles of no going to n2 and 2 moles of h2.
00:08
There are two proposed mechanisms.
00:12
We know that the rate law for the reaction is the rate expressed as the change in concentration of n2 over the change in time.
00:19
Is k multiplied by the concentration of h2 and the concentration of n0 squared.
00:25
So it's first order with respect to h2 and second order with respect to no.
00:29
In order for us to get this rate law from the first mechanism, it asks under what conditions does this mechanism give the observed rate law? the first step needs to be slow in the rate determining step, and the second step will be fast.
00:48
If the first step is slow, then we can write the rate law from its molecularity, where rate will be equal to the concentration of h2, multiplied by the concentration of n0 squared, which is the observed rate law.
01:03
Therefore, k -1 is the observed k -value.
01:09
For the second mechanism, in order for it to be plausible, we need to have the first step be fast and reversible, and the second step be the slow or rate -determining step.
01:25
We can then write the rate law for the second step in terms of its molecularity and related to the overall rate law.
01:35
The rate law for the second step will be rate, if it's slow in the rate determining step, rate equals k2, multiplied by the concentration of h2 and the concentration of n202...