00:02
Hello students, in this question we have to calculate the magnetic field.
00:06
Now we know that the magnetic force is equals to qv cross b.
00:13
So v and b are perpendicular to each other.
00:16
So this will be equal to the qvb and the f is equals to mv square by r centripetal force.
00:27
So this and the v, 1v is cancelled.
00:33
So the b will be equal to the mv upon q into r, equation number 1.
00:40
Next, in this question given as a covered length by the particle which is given in this question which is electron.
00:52
So this covered the quarter length of the circumference of a circle.
00:57
So we can write this is equals to 2 pi r by 4.
01:02
So this will be equal to the pi r by 2 or we can write r is equals to 2l upon pi, equation number 2.
01:12
Now we will put the value of the r in the equation number 1.
01:16
So b will be equal to the mv pi upon 2ql.
01:23
Now we will substitute all the values.
01:24
Mass of the electron is 1 .6 into 10 to the power minus 20 minus 27 kilogram into velocity is given as 1 .2 kilometer per second.
01:37
So 10 to the power 3 meter per second into pi is 3 .14 and 2 into charge is 1 .6 into 10 to the power minus 19 and the covered length is given as 1 .18 centimeter, 1 .18 into 10 to the power minus 2 meter.
01:57
So after calculation we will get the b is equals to 1 .67 into 10 to the power minus 3 tesla.
02:10
Hello students, in this question the value of velocity of the electron and magnetic field is given.
02:16
Now we have to calculate the electric field but in this question given as the electron is not deflecting.
02:22
So the force will be zero.
02:24
Now force is equals to qe plus qv cross b.
02:31
So force is not deflecting that is electron is so force will be equal to the zero...