Question

28) A crane lifts a 425 kg steel beam vertically upward a distance of 95 m. How much work does the crane do on the beam if the beam accelerates upward at 1.8 m/s^2? Neglect frictional forces. Show work. A) 4.7 * 10^5 J B) 2.7 * 10^5 J C) 3.2 * 10^5 J D) 4.0 * 10^5 J 29) When a car of mass 1167 kg accelerates from 10.0 m/s to some final speed, 4.00 * 10^5 J of work are done: Find this final speed. Show work. A) 28.0 m/s B) 22.4 m/s C) 25.2 m/s D) 30.8 m/s

Name: 28 a crane lifts a 425 kg steel beam vertically upward a distance of 95m how much work does the crane do on the beam if the beam accelerates upward at 18 ms2 neglect frictional forces show w 13898
Uploaded: 2022-02-27T12:58:04-08:00
Duration: 1 min 34 s
Channel: Keerti J
Description: 28 a crane lifts a 425 kg steel beam vertically upward a distance of 95m how much work does the crane do on the beam if the beam accelerates upward at 18 ms2 neglect frictional forces show w 13898

          28) A crane lifts a 425 kg steel beam vertically upward a distance of 95 m. How much work does the crane do on the beam if the beam accelerates upward at 1.8 m/s^2? Neglect frictional forces. Show work. A) 4.7 * 10^5 J B) 2.7 * 10^5 J C) 3.2 * 10^5 J D) 4.0 * 10^5 J
29) When a car of mass 1167 kg accelerates from 10.0 m/s to some final speed, 4.00 * 10^5 J of work are done: Find this final speed. Show work. A) 28.0 m/s B) 22.4 m/s C) 25.2 m/s D) 30.8 m/s

Added by Roberto D.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Keerti J

02/27/2022

Step 1

Given: Mass of steel beam (m) = 425 kg Height lifted (h) = 95 m Acceleration (a) = 1.8 m/s^2 Acceleration due to gravity (g) = 9.81 m/s^2 Work done = Force x Distance Force = Mass x Acceleration due to gravity Force = 425 kg x 9.81 m/s^2 = 4164.25 N Work done = Show more…

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28) A crane lifts a 425 kg steel beam vertically upward a distance of 95 m. How much work does the crane do on the beam if the beam accelerates upward at 1.8 m/s^2? Neglect frictional forces. Show work. A) 4.7 * 10^5 J B) 2.7 * 10^5 J C) 3.2 * 10^5 J D) 4.0 * 10^5 J 29) When a car of mass 1167 kg accelerates from 10.0 m/s to some final speed, 4.00 * 10^5 J of work are done: Find this final speed. Show work. A) 28.0 m/s B) 22.4 m/s C) 25.2 m/s D) 30.8 m/s