00:01
Here we have a series rlc circuit and here this series rlc circuit is connected to a ac supply with supply voltage epsilon.
00:09
Suppose current flowing through this series rlc circuit is equal to i.
00:14
Here both i and epsilon are the rms value.
00:18
Now here given that this series rlc circuit is at resonance.
00:24
And we know at the condition of resonance, inductive reactance of the circuit becomes equal to capacitive reactance of the circuit.
00:32
Circuit.
00:33
Now here we assume that xl is equal to x c is equal to x.
00:38
Now total impedance of this circuit at the condition of resonance is given by z equals to r plus j xl minus j x c.
00:50
Now from this we have xl is equal to x equals to x so from this we obtain z equals to r plus j x minus x and from this we obtain z equals to r plus j x minus x and from this we that means at the condition of resonance this series rlc circuit behaves like a resistive circuit.
01:12
And here if we take supply voltage as a reference, then the supply voltage becomes equal to epsilon angle 0 degree.
01:21
Now by using kirchop voltage low, we obtain current i equals to epsilon angle 0 over z.
01:29
Now from this we obtain current i equals to epsilon of angle 0 degree.
01:37
Now suppose voltage across this resistance is equal to vr...