29. A first-order reaction has a rate constant of 1.4 x 10^-3/s. How many minutes will it take for the concentration of the reactant to drop to 10% of the original concentration? A. 8 min B. 27 min C. 73 min
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The half-life of a first-order reaction can be calculated using the formula t1/2 = ln(2) / k, where t1/2 is the half-life and k is the rate constant. t1/2 = ln(2) / 1.4 x 10^-3/s t1/2 = 0.693 / 1.4 x 10^-3/s t1/2 = 495 seconds Show more…
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