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Hi.
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Here in this given problem the diagram shows three particles, particle a, particle b and particle c.
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The gap between a and b that is given as 0 .500 meter and the gap between b and c.
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This is given as 0 .250 meter.
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Mass of the particles is given as ma is equal to 363 kilogram mb this is equal to 517 kilogram and at last m c this is 154 kilogram now we have to find in three parts of the problem we have to find net gravitational force experienced by all these three particles.
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So, let us start with a.
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A will be experiencing two forces, two gravitational forces.
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One because of b means f experienced by a because of b, f -a -b.
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And another due to c, f experienced by a due to c.
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Both are in the same direction, as these are force of attraction between a and b and c.
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Then come to b, b will be attract.
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By a, f at b due to a towards left, and it will be attracted by c, f at b due to c towards right.
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Then the gravitational forces at c, one is f at c due to b and another is in the same direction towards left, f at c due to a...