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2. A Vanadium (V) has a BCC crystal structure a density of 5.96 g/cm³ & an atomic weight of 50.9 g/mol. Take ? = (nA /VcNA). NA=6.023×10²³atoms/mol. a. Calculate the radius of a Vanadium atom (r) b. Calculate the side a of the vanadium (V) unit cell. c. Calculate the APF for the vanadium. d. Based on following, compare between the Vanadium and the Gold. Vanadium Gold Crystal Structure BCC FCC Strength Ductility Malleability

          2. A Vanadium (V) has a BCC crystal structure a density of 5.96 g/cm³ & an atomic weight of 50.9 g/mol. Take
? = (nA /VcNA).
NA=6.023×10²³atoms/mol.
a. Calculate the radius of a Vanadium atom (r)
b. Calculate the side a of the vanadium (V) unit cell.
c. Calculate the APF for the vanadium.
d. Based on following, compare between the Vanadium and the Gold.
Vanadium Gold
Crystal Structure BCC FCC
Strength
Ductility
Malleability

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2. A Vanadium (V) has a BCC crystal structure a density of 5.96 g/cm³ an atomic weight of 50.9 g/mol. Take
? = (nA /VcNA).
NA=6.023×10²³atoms/mol.
a. Calculate the radius of a Vanadium atom (r)
b. Calculate the side a of the vanadium (V) unit cell.
c. Calculate the APF for the vanadium.
d. Based on following, compare between the Vanadium and the Gold.
Vanadium Gold
Crystal Structure BCC FCC
Strength
Ductility
Malleability

Added by Daniel B.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

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Solved by Expert Sri K

01/01/2023

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Calculate the atomic weight of vanadium (50.9 g/mol): Show more…

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A Vanadium (V) has a BCC crystal structure a density of 5.96 g/cm³ & an atomic weight of 50.9 g/mol. Take ρ = (nA /VcNA). NA=6.023×10²³atoms/mol. a. Calculate the radius of a Vanadium atom (r) b. Calculate the side a of the vanadium (V) unit cell. c. Calculate the APF for the vanadium. d. Based on following, compare between the Vanadium and the Gold. Vanadium Gold Crystal Structure BCC FCC Strength Ductility Malleability

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