Question

2FeS + H2CO3 ? 2FeO + 1/n (CHOH)n + 2S 1st attempt Part 1 (1 point) How much FeO is produced starting with 1.30 g FeS and 0.518 moles of H2CO3 if the reaction results in a 77.7% yield? g Part 2 (1 point) If one of the carbon-containing products has a molar mass of 3.00 !! 10" g/mol, what is the chemical formula of the product? (CHOH)

          2FeS + H2CO3 ? 2FeO + 1/n (CHOH)n + 2S

1st attempt

Part 1 (1 point)
How much FeO is produced starting with 1.30 g FeS and 0.518 moles of H2CO3 if the reaction results in a 77.7% yield?
g

Part 2 (1 point)
If one of the carbon-containing products has a molar mass of 3.00 !! 10" g/mol, what is the chemical formula of the product?
(CHOH)

2FeS + H2CO3 ? 2FeO + 1/n (CHOH)n + 2S

1st attempt

Part 1 (1 point)
How much FeO is produced starting with 1.30 g FeS and 0.518 moles of H2CO3 if the reaction results in a 77.7% yield?
g

Part 2 (1 point)
If one of the carbon-containing products has a molar mass of 3.00 !! 10" g/mol, what is the chemical formula of the product?
(CHOH)

Added by Becky L.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sri K

11/06/2022

Step 1

Given: Mass of FeS = 1.30 g Molar mass of FeS = 88 g/mol Moles of FeS = Mass/Molar mass Moles of FeS = 1.30 g / 88 g/mol Moles of FeS = 0.01477 mol Show more…

Show all steps

Thanks for your feedback!

2FeS + H2CO3 -> 2FeO + 1/n(CHOH)n + 2S 1st attempt Part 1 (1 point) How much FeO is produced starting with 1.30 g FeS and 0.518 moles of H2CO3 if the reaction results in a 77.7% yield? g Part 2 (1 point) If one of the carbon-containing products has a molar mass of 3.00 × 10^2 g/mol, what is the chemical formula of the product? (CHOH)