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2. HF(aq) + H2O(l) \(\rightleftharpoons\) H3O+(aq)+F-(aq) The equation above represents the acid ionization equilibrium for HF. To prepare a buffer with pH ? 3.50, 4.20 g of NaF(s) should be added to 500.0 mL of 0.100 M HF(aq). The buffer is accidentally prepared using 90% pure NaF (s) instead of 99% pure NaF (s). Assume that the impurities in the NaF (s) samples are inert. Which of the following explains how the error affects the pH and capacity of the buffer? (A) The pH is slightly higher than 3.50 and it has a lower capacity for the addition of acids because less than 4.20 g of NaF(s) was added. (B) The pH is slightly higher than 3.50 and it has a higher capacity for the addition of acids because more than 4.20 g of NaF(s) was added. (C) The pH is slightly lower than 3.50 and it has a lower capacity for the addition of acids because less than 4.20 g of NaF(s) was added. (D) The pH is slightly lower than 3.50 and it has a higher capacity for the addition of acids because more than 4.20 g of NaF(s) was added.

          2. HF(aq) + H2O(l) \(\rightleftharpoons\) H3O+(aq)+F-(aq)
The equation above represents the acid ionization equilibrium for HF. To prepare a buffer with pH ? 3.50,
4.20 g of NaF(s) should be added to 500.0 mL of 0.100 M HF(aq). The buffer is accidentally prepared using
90% pure NaF (s) instead of 99% pure NaF (s). Assume that the impurities in the NaF (s) samples are inert.
Which of the following explains how the error affects the pH and capacity of the buffer?
(A) The pH is slightly higher than 3.50 and it has a lower capacity for the addition of acids because less than
4.20 g of NaF(s) was added.
(B) The pH is slightly higher than 3.50 and it has a higher capacity for the addition of acids because more than
4.20 g of NaF(s) was added.
(C) The pH is slightly lower than 3.50 and it has a lower capacity for the addition of acids because less than
4.20 g of NaF(s) was added.
(D) The pH is slightly lower than 3.50 and it has a higher capacity for the addition of acids because more than
4.20 g of NaF(s) was added.

2. HF(aq) + H2O(l) ⇌ H3O+(aq)+F-(aq)
The equation above represents the acid ionization equilibrium for HF. To prepare a buffer with pH ? 3.50,
4.20 g of NaF(s) should be added to 500.0 mL of 0.100 M HF(aq). The buffer is accidentally prepared using
90% pure NaF (s) instead of 99% pure NaF (s). Assume that the impurities in the NaF (s) samples are inert.
Which of the following explains how the error affects the pH and capacity of the buffer?
(A) The pH is slightly higher than 3.50 and it has a lower capacity for the addition of acids because less than
4.20 g of NaF(s) was added.
(B) The pH is slightly higher than 3.50 and it has a higher capacity for the addition of acids because more than
4.20 g of NaF(s) was added.
(C) The pH is slightly lower than 3.50 and it has a lower capacity for the addition of acids because less than
4.20 g of NaF(s) was added.
(D) The pH is slightly lower than 3.50 and it has a higher capacity for the addition of acids because more than
4.20 g of NaF(s) was added.

Added by Kurt G.

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