Question

2. It is required to select a flat belt drive for a fan running at 360r.p.m which is driven by a 10kW, 1440 rpm motor. The belt is open type and the space is available for a centre distance of 2m approximately. The belt velocity should be between 17.8 to 22.9 m/s. 3. Determine the number of V-belts required to transmit 30 kW power under the following conditions : | | Smaller Pulley | Larger pulley | | :--- | :--- | :--- | | Speed | 1120 rpm | 280rpm | | Pitch diameter | 225 mm | 900 mm | | Pulley groove angle | 34° | 34° | Maximum working load per belt = 560 N Coefficient of friction = 0.15 Centre distance between pulleys = 875 mm Mass of belt = 0.3 kg/m.

          2. It is required to select a flat belt drive for a fan running at 360r.p.m which is driven by a 10kW, 1440
rpm motor. The belt is open type and the space is available for a centre distance of 2m approximately.
The belt velocity should be between 17.8 to 22.9 m/s.

3. Determine the number of V-belts required to transmit 30 kW power under the following conditions :

| | Smaller Pulley | Larger pulley |
| :--- | :--- | :--- |
| Speed | 1120 rpm | 280rpm |
| Pitch diameter | 225 mm | 900 mm |
| Pulley groove angle | 34° | 34° |

Maximum working load per belt = 560 N
Coefficient of friction = 0.15
Centre distance between pulleys = 875 mm
Mass of belt = 0.3 kg/m.

Show more…

2. It is required to select a flat belt drive for a fan running at 360r.p.m which is driven by a 10kW, 1440
rpm motor. The belt is open type and the space is available for a centre distance of 2m approximately.
The belt velocity should be between 17.8 to 22.9 m/s.

3. Determine the number of V-belts required to transmit 30 kW power under the following conditions :

| | Smaller Pulley | Larger pulley |
| :— | :— | :— |
| Speed | 1120 rpm | 280rpm |
| Pitch diameter | 225 mm | 900 mm |
| Pulley groove angle | 34° | 34° |

Maximum working load per belt = 560 N
Coefficient of friction = 0.15
Centre distance between pulleys = 875 mm
Mass of belt = 0.3 kg/m.

Added by Bradley P.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

07/16/2023

Step 1

For the flat belt drive, we need to calculate the required belt speed and select a belt that falls within the given range of 17.8 to 22.9 m/s. Belt speed = (motor speed x motor pulley diameter) / (fan speed x fan pulley diameter) = (1440 x Dm) / (360 x Df) Show more…

Show all steps

lock

Thanks for your feedback!

2. It is required to select a flat belt drive for a fan running at 360r.p.m which is driven by a 10kW, 1440 rpm motor. The belt is open type and the space is available for a centre distance of 2m approximately. The belt velocity should be between 17.8 to 22.9 m/s. 3. Determine the number of V-belts required to transmit 30 kW power under the following conditions : Smaller Pulley: Speed 1120 rpm, Pitch diameter 225 mm, Pulley groove angle 34° Larger pulley: Speed 280rpm, Pitch diameter 900 mm, Pulley groove angle 34° Maximum working load per belt = 560 N Coefficient of friction = 0.15 Centre distance between pulleys = 875 mm Mass of belt = 0.3 kg/m.

Play audio

Feedback

Powered by NumerAI

Adi S and 56 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Recommended Videos

Recommended Textbooks

Transcript

00:01 Power is equal to 30 kilowatt.

00:05 D is given as 225 mm.

00:08 Capital d is given as 900 mm.

00:12 Theta is equal to 34 degrees.

00:15 Load is equal to 560 newtons.

00:18 Mu is equal to 0 .15.

00:21 C is equal to 875 mm.

00:24 M is equal to 0 .3 kg per m.

00:28 Now what are the objectives? first we have to determine the number of v -belts required.

00:33 So the explanation behind it is that a v -belt it is given and then transmits power to the shaft.

00:39 Two different pulleys and the specifications here we have been given.

00:44 The angle of grab from the smaller pulley.

00:47 So here it is alpha which is 180 minus 2 sine inverse capital d minus small d divided by 2c which is equal to 180 minus 2 sine inverse.

00:58 We need to insert the values here.

01:01 So 900 minus 225 divided by 2 multiplied by 875.

01:05 From here this alpha will come out to be equal to 134 .62 degrees.

01:11 Now belt tension it is equal to t is 0 .15 multiplied by 134 .62 divided by 180 multiplied by pi divided by sine 34 divided by 2.

01:26 So from here the value of t will come out to be equal to 3 .337...

Ace is your personal tutor. It breaks down any question with clear steps so you can learn.

Start Using Ace

Continue solving this problem

Create a free account to:

View full step-by-step solution
Ask follow-up questions with Ace AI
Save progress and study later