00:01
We'd like to find s and t.
00:03
So we're given our initial velocity.
00:06
We can write that our height and our y direction is equal to our initial velocity times sign of our angle, which is 30 degrees, times t plus 4 .9t squared.
00:20
But our height and our y direction is just our distance times sign of that angle, which is 14 degrees, equal to.
00:31
To 141, sine of 30 times t, plus 4 .9 t squared, or minus 4 .9 t squared.
00:43
So we can go ahead and simplify this.
00:46
We have sign of 14 degrees, which is 0 .241 times s equal to 141, sign of 30 degrees.
00:55
So that is 70 .5t minus 4 .9 t squared.
01:00
This is quadratic in t.
01:03
Now in the x direction, we have our heighten our x direction is v .0 cosine 30 degrees times t.
01:12
So we can use our other equation of motion...