Question

(3) (10 pts) The ionization energy (IE) of an electron from an atom can be estimated according to Koopman's theorem which states that IE ? –En, where En is the orbital energy from which the electron is removed. (a) Calculate the ground state ionization energy for He?, using the simplified energy expression for hydrogenic systems. (b) Without doing any calculations, predict how IE changes in the across the series H, He?, Li²?, Be³?, B??, C??, N??, O??, F?? and Ne??. Briefly explain reasoning behind your order.

          (3) (10 pts) The ionization energy (IE) of an electron from an atom can be estimated according to Koopman's theorem which states that IE ? –En, where En is the orbital energy from which the electron is removed.

(a) Calculate the ground state ionization energy for He?, using the simplified energy expression for hydrogenic systems.

(b) Without doing any calculations, predict how IE changes in the across the series H, He?, Li²?, Be³?, B??, C??, N??, O??, F?? and Ne??. Briefly explain reasoning behind your order.
        
Show more…
(3) (10 pts) The ionization energy (IE) of an electron from an atom can be estimated according to Koopman's theorem which states that IE ? –En, where En is the orbital energy from which the electron is removed.

(a) Calculate the ground state ionization energy for He?, using the simplified energy expression for hydrogenic systems.

(b) Without doing any calculations, predict how IE changes in the across the series H, He?, Li²?, Be³?, B??, C??, N??, O??, F?? and Ne??. Briefly explain reasoning behind your order.

Added by Eric F.

Close

Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
The ionization energy (IE) of an electron from an atom can be estimated according to Koopman's theorem which states that IE ā‰ˆ –En, where En is the orbital energy from which the electron is removed. (a) Calculate the ground state ionization energy for Heⁱ, using the simplified energy expression for hydrogenic systems. (b) Without doing any calculations, predict how IE changes in the across the series H, Heⁱ, Li²ⁱ, Be³ⁱ, B⁓ⁱ, C⁵ⁱ, N⁶ⁱ, O⁷ⁱ, F⁸ⁱ and Ne⁹ⁱ. Briefly explain reasoning behind your order.
Close icon
Play audio
Feedback
Powered by NumerAI
Kathleen Carty Jennifer Stoner
Danielle Fairburn verified

Sri K and 82 other subject Chemistry 101 educators are ready to help you.

Ask a new question

*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Key Concepts

-
Key Concept
Premium Feature
Explore the core concept behind this problem.
Play button
Key Concept
Premium Feature
Explore the core concept behind this problem.
Your browser does not support the video tag.

*

Recommended Videos

-
a-write-the-electron-configuration-for-mathrmli-and-estimate-the-effective-nuclear-charge-experience

(a) Write the electron configuration for $\mathrm{Li}$, and estimate the effective nuclear charge experienced by the valence electron. (b) The energy of an electron in a one-electron atom or ion equals $\left(-2.18 \times 10^{-18} \mathrm{~J}\right)\left(\frac{Z^{2}}{n^{2}}\right)$ where $Z$ is the nuclear charge and $n$ is the principal quantum number of the electron. Estimate the first ionization energy of Li. (c) Compare the result of your calculation with the value reported in Table 7.4 and explain the difference. (d) What value of the effective nuclear charge gives the proper value for the ionization energy? Does this agree with your explanation in $(\mathrm{c}) ?$

Chemistry The Central Science

a-write-the-electron-configuration-for-l-i-and-estimate-the-effective-nuclear-charge-experienced-by-

(a) Write the electron configuration for $L i$ and estimate the effective nuclear charge experienced by the valence electron. (b) The energy of an electron in a one-electron atom or ion equals $\left(-2.18 \times 10^{-18} \mathrm{~J}\right)\left(\frac{Z^{2}}{n^{2}}\right),$ where $Z$ is the nuclear charge and $n$ is the principal quantum number of the electron. Estimate the first ionization energy of Li. (c) Compare the result of your calculation with the value reported in Table 7.4 and explain the difference. (d) What value of the effective nuclear charge gives the proper value for the ionization energy? Does this agree with your explanation in part (c)?

Chemistry: The Central Science in SI Units, Global Edition

the-ionization-energies-of-mathrmli-mathrmbe-mathrmb2-and-mathrmc3-are-respectively-52017573659-and-

The ionization energies of $\mathrm{Li}, \mathrm{Be}^{+}, \mathrm{B}^{2+},$ and $\mathrm{C}^{3+}$ are respectively, $520,1757,3659,$ and $6221 \mathrm{kJ} \mathrm{mol}^{-1} .$ The ionization energies $\mathrm{Na}, \mathrm{Mg}^{+}, \mathrm{Al}^{2+},$ and $\mathrm{Si}^{3+}$ are (from Table 9.4 ) $495.8,1451,2745,$ and $4356 \mathrm{kJ} \mathrm{mol}^{-1} .$ Plot a graph of the square roots of the ionization energies Versus the nuclear charge for these two series. Explain the observed relationship with the aid of Bohr's expression for the binding energy of an electron in a one-electron atom.

General Chemistry: Principles and Modern Applications


*

Recommended Textbooks

-
Chemistry: Structure and Properties

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition
achievement 1,134 solutions
Chemistry The Central Science

Chemistry The Central Science

Theodore L. Brown 14th Edition
achievement 1,540 solutions
Chemistry

Chemistry

Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste 10th Edition
achievement 1,979 solutions

*

Transcript

-
0:00 Hello everyone.
00:01 So the first part of the question asks us to find the ionization energy for helium -positive ion considering hydrogenic systems.
00:11 So the formula for ionization energy for hydrogenic systems is negative of 13 .6 multiplied by z squared divided by n square where z is the atomic number while n is the orbit number so for helium positive we have negative of 13 .6 the atomic number of helium is 2 so it will be 2 squared by the orbit number is 1 square so this gives us 54 .4 electron volts of ionization energy for the second part if we look at the formula we can clearly see that the ionization energy for the systems or ions is directly proportional to the atomic number the square of atomic number so as z increases that is the atomic number increases the ionization energy increases as well...
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Join the community

18,000,000+

Students on Numerade


Trusted by students at 8,000+ universities

Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever