3. [10 pts] Use strong induction to prove that C(n) = 2^n + 3 is a solution to the recurrence C(0) = 4, C(1) = 5, and, for all n ? Z^+, n > 1 C(n) = 3 · C(n - 1) - 2 · C(n - 2) .
Added by Margaret G.
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Step 1
For n = 1: C(1) = 2(1) + 3 = 5, which matches the given initial value C(1) = 5. Therefore, the base cases hold true. ** Show more…
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