00:01
For part a, we can find the initial angular velocity.
00:03
This would be equalling the tangential velocity divided by the initial radius.
00:08
So this would be equalling 1 .30 meters per second.
00:14
This would be divided by 2 .30 times 10 to the negative second meters.
00:20
This is equaling 56 .5 radiance per second.
00:26
That would be our final answer for part a.
00:30
For part b then the final angular velocity would be equalling the tangential velocity divided by radius final.
00:38
This is equaling again 1 .30 meters per second divided by here now 5 .80 times 10 to the negative second meters.
00:52
And this is equaling 22 .4 radians per second.
00:58
This would be our final answer for part b.
01:02
Now for part c, we know that the duration of the recording is delta t.
01:09
This is going to be equaling to 74 minutes, or we can say multiplied by 60 seconds for every minute.
01:18
This is giving us plus 33 seconds, and this is giving us 4 ,473 seconds.
01:27
So at this point, we can say that then the average angular acceleration would be equaling to omega -final minus omega -3.
01:36
Initial divided by delta t so this is equaling 22 .4 minus 56 .5 radiance per second divided by 4 ,473 seconds...