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What must be the vertical velocity V of the air for the droplet to remain suspended in the air? Water droplet T=25°C, Pwater=997 kg/m³ D=38 μm D: Diameter Air Tair=25°C, p=1.184 kg/m³ μ=1.849 x 10⁻⁵ kg/m·s 

          What must be the vertical velocity V of the air for the droplet to remain suspended in the air?
Water droplet
T=25°C, Pwater=997 kg/m³
D=38 μm
D: Diameter
Air
Tair=25°C,
p=1.184 kg/m³
μ=1.849 x 10⁻⁵ kg/m·s
3 30p what must be the vertical velocity v of the air for the droplet to remain suspended in the air water droplet t25c pwater997 kgm3 d38um d diameter air tair25c p1184 kgm3 1849 10 5 kgm s 32376

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University Physics with Modern Physics
Hugh D. Young 14th Edition
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What must be the vertical velocity V of the air for the droplet to remain suspended in the air? Water droplet T=25°C, Pwater=997 kg/m³ D=38 μm D: Diameter Air Tair=25°C, p=1.184 kg/m³ μ=1.849 x 10⁻⁵ kg/m·s
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Transcript

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0:00 I.
00:01 This is a question based on finding the terminal velocity.
00:04 So, we have the value of diameter and the value of density of this sphere and temperature and the density of water at 20 degree celsius are given and the value of mu is also given.
00:21 So, we have to find also cd is given.
00:25 So, we have to find the value of terminal velocity v.
00:29 So, now, in the first part of the question we have to find area which is equal to pi by 4 into d square.
00:36 So, this is pi by 4 into d is 13 millimeters that is 13 into 10 power minus 3 millimeter which is the whole square.
00:46 So, this will be equal to 13 point or 1 .327 into 10 power minus 4 meter square.
00:54 Then we have the value of so, then we have f naught is equal to 1 by 2 into c naught a into rho of water into v square.
01:07 So, we have this is equal to half into the value of c naught is 0 .5 given in the question area is 1 .327 into 10 power minus 4 and density of water is 998 into v square where v is the terminal velocity.
01:24 So, this is 0 .0331167 v square.
01:31 Then by principle of beyoncé.
01:34 So, beyoncé we have w or the weight is given by rho g into v where rho is the density of water.
01:43 So, on substituting the values and v is the volume...
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