00:01
So, let us have a look on this question.
00:01
So, in this question we have given a capacitor of capacitance c and it is connected to a battery of voltage v.
00:10
Now, when this capacitor fully charged with charge q, then this battery will be disconnected like this.
00:18
This is the final condition.
00:20
And after disconnecting this battery what we are doing, we are just reducing this separation with the three times, means distance between the plate is initially d.
00:30
So, finally, it will be d by 3.
00:32
This is the final condition.
00:34
So, the question is what is the capacitance and voltage after this separation.
00:39
So, initially voltage is simply v volt and capacitance is c and we can write it as c is equal to a epsilon 0 by d...