3) (4 pts) Find the values for V, I1, and I2 in the...

Transcript

00:01 Alright dear lenders let's draw the circuit diagram first here we have a battery source this is positive this is negative terminal with this battery source we have a register connected this way and there is another register connected this way and this is connected with the negative terminal of the battery and with this node we have another source connected this way and this source is connected with another register and this is finally connected with this node let's label this the components of this circuit all right the the emf of this voltage source is given by v1 and it is equal to 24 volts all right this register is level as r1 and it is equal to 8 ooms this voltage source is labeled as v2 and it is of 10 and this register it has been labeled as r3 and it is of 4 ohm and finally this register it has been labeled as r2 and it is of 6 ohm all right now the current in this branch or the current through this register it has been labeled as i1 and the current in this branch all right it has been labeled as i3 or the current which is flowing through this register and the current which is flowing through this register it has been labeled as i2 all right now let's call this node a and the potential or the voltage of this know is let's say denoted with va all right first of all we will use nodal voltage analysis method 8 node a, all right? according to this method, sum of all the currents to this node is equal to 0.

02:20 So there are three branches connected with this node.

02:23 It means there should be three currents.

02:25 One, this current, the current in this branch, the current in this branch, and the current in this branch, the sum of these currents at this node should be equal to 0 according to this method.

02:37 So first of all let's start from this branch.

02:40 The current in this branch should be equal to this potential there is v a minus this potential minus v1 minus this potential let's say put this potential is connected with ground at zero volt minus zero divided by total resistance in this branch this is only r2 so this is the current in this branch plus the current in this branch is this voltage minus this voltage the upper voltage is va minus the lower voltage is 0 divided by the resistance is r1 plus the current in this branch is equal to this potential minus this potential va minus v2 minus this potential zero divided by resistance there is only one resistance there is r3 is equal to now let's plug in the values we should be as it is minus the value of v1 is 24 volts this zero is as it is the value of r2 is six oom plus v a divided by the value of r1 is eight oom plus v a minus the value of v2 is 10 oom divided by the value of r3 is four this is equal to zero from this equation we get the value of va is equal to 12 volts...

Question

3) (4 pts) Find the values for $V$, $I_1$, and $I_2$ in the following circuit. $12 \text{ mA}$ $I_1 + I_2$ $V$ $8K$ $16K$

Question

3) (4 pts) Find the values for $V$, $I_1$, and $I_2$ in the following circuit. $12 \text{ mA}$ $I_1 + I_2$ $V$ $8K$ $16K$

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