00:01
This is the diagram given to us.
00:04
This is point a while this is point b.
00:08
Now, these are the strings tied to the load.
00:13
The load is this with weight 1600 kg.
00:21
This is the center line marked.
00:24
Now the distance from center to b is 400 millimeters while from a to center is 1100 millimeters.
00:38
Let us consider this angle as theta 1 while this angle as theta 2.
00:45
Force acting towards this is tac because we will consider this point as c.
00:51
This force will be tbc.
00:56
Now this distance is given to us as 960 millimeters.
01:02
This is the diagram given to us and details.
01:06
Now we would be taking tan theta is equals to that would be 1100 upon 960.
01:16
Right dividing this we would be getting 55 upon 48.
01:23
The value of tan theta 1 then tan theta 2 again putting the formula for tan theta we have here 400 upon 960.
01:39
Which gives us the value of tan theta 2 to be dividing this we have 5 by 12, 5 divided by 12.
01:51
These are the two values of tan theta 1 and tan theta 2.
01:56
Let us mark those.
01:59
Now applying the formula we have tan we would take tac that is the force cos theta 1 plus tbc cos theta 2 will be equal to the total weight that is 1600 into g...