A 500-kg elevator is pulled upward with a constant force of 5500 N for a distance of 50.0 m. (a) What is the work done by the 5500 N force? (b) What is the work done by gravity? (c) What is the net work done on the elevator?
Added by Heather H.
Step 1
In this case, the force and the motion are in the same direction (upward), so θ = 0 and cos θ = 1. Show more…
Show all steps
Your feedback will help us improve your experience
Prabhu Ramji and 71 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A 600-kg elevator is moved upward by a constant force of 6500 N for a distance of 60.0 m.What is the net work done on the elevator?
Ankur S.
(a) Calculate the work done on a 1500-kg elevator car by its cable to lift it 40.0 m at constant speed, assuming friction averages 100 N. (b) What is the work done on the lift by the gravitational force in this process? (c) What is the total work done on the lift?
Eduard S.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD
