3.) A 70 kg human sprinter can accelerate from rest to 10 m/s in 3.0 s. During the same time interval, a 30 kg greyhound can go from rest to 20 m/s. What is the average power output of each? Average power over a time interval ?t is ?E/?t.
Added by Gonzalo L.
Close
Step 1
5 * mass * velocity^2 KE = 0.5 * 70 kg * (10 m/s)^2 KE = 0.5 * 70 kg * 100 m^2/s^2 KE = 3500 J Show more…
Show all steps
Your feedback will help us improve your experience
Sahil Kumar and 82 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A 70 kg human sprinter can accelerate from rest to 10 m/s in 3.0 s. During the same time interval, a 30 kg greyhound can go from rest to 20 m/s. What is the average power output of each? Average power over a time interval Δt is ΔE/Δt.
Sahil K.
A $70 \mathrm{~kg}$ human sprinter can accelerate from rest to $10 \mathrm{~m} / \mathrm{s}$ in $3.0 \mathrm{~s} .$ During the same interval, a $30 \mathrm{~kg}$ greyhound can accelerate from rest to $20 \mathrm{~m} / \mathrm{s}$. Compute (a) the change in kinetic energy and (b) the average power output for each.
(a) What is the power output in watts and horsepower of a 70.0-kg sprinter who accelerates from rest to 10.0 m/s in 3.00 s? (b) Considering the amount of power generated, do you think a well-trained athlete could do this repetitively for long periods of time?
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD