00:01
Before calculating anything associated with the metal, they just want us to calculate q water.
00:07
Q water will just be equal to specific heat of water, mass of water, change in temperature of water.
00:15
Specific heat of water is 4 .184 joules per gram degrees celsius.
00:21
The mass of the water, assuming the density of 1 gram per mill liter, will just be equal to the milliliters.
00:31
Converted to grams, 48 .3 mil liters will become 48 .3 grams and then a change in temperature.
00:42
The final temperature of the water was 32 .8 degrees celsius.
00:48
The initial temperature was 23 .4 degrees celsius and we get 1 ,89 .6 joules or just 1900 joules to four significant figures.
01:09
Well, let's see.
01:10
This difference right here is only going to be two significant figures.
01:16
So i guess we're only justified to two significant figures.
01:24
Then if instead of using this, we use the 1 .00 calories per gram degree celsius...