Question

#3. A coherent FSK system operates over VHF radio. The Eb / NO is +12 db. The pres carrier power is 50 watts. A change is made to 2-PSK at the same Eb / NO. a. What was the original BER with coherent FSK? b. What is the new BER with 2-PSK? c. What new lower carrier power can we use if we return to the original BER bu 2-PSK?

          #3. A coherent FSK system operates over VHF radio. The Eb / NO is +12 db. The pres
carrier power is 50 watts. A change is made to 2-PSK at the same Eb / NO.
a. What was the original BER with coherent FSK?
b. What is the new BER with 2-PSK?
c. What new lower carrier power can we use if we return to the original BER bu
2-PSK?
        
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#3. A coherent FSK system operates over VHF radio. The Eb / NO is +12 db. The pres
carrier power is 50 watts. A change is made to 2-PSK at the same Eb / NO.
a. What was the original BER with coherent FSK?
b. What is the new BER with 2-PSK?
c. What new lower carrier power can we use if we return to the original BER bu
2-PSK?

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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A coherent FSK system operates over VHF radio. The Eb/NO is +12 dB. The pre-carrier power is 50 watts. A change is made to 2-PSK at the same Eb/NO. a. What was the original BER with coherent FSK? b. What is the new BER with 2-PSK? c. What new lower carrier power can we use if we return to the original BER but 2-PSK?
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00:01 In this question s of t is given which is 1 plus 0 .2 this is cos 2 pi fx and then we have this cos 2 pi fc t.
00:15 So now we have the value basically this is fm.
00:19 Okay, so fc is 75 megahertz and fm is 120 hertz.
00:27 So first of all in the first part we have to calculate the lambda c.
00:30 So lambda c is 3 divided by f that equal to 3 multiplied by 10 power 8 divided by 75 multiplied by 10 power 6.
00:40 So we get this value as 4.
00:41 This is the value for lambda c.
00:44 Now for the antenna lambda c divided by 2 the length is equal to lambda divided by 4.
00:50 So it is lambda c divided by 2 divided by 4.
00:53 So 4 divided by 8 that equal to 0 .5 meter.
00:57 This will be the length...
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